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A simple pendulum, 1.00 m in length, is released from rest when the support string is at an angle of 35.0 from the vertical. What is the speed of the suspended mass at the bottom of the swing? (g = 9.80 m/s2 and ignore air resistance)

Answer :

fawwadsaeed

Answer:

Explanation:

Length = 1.00 m

If the length is 1.0, the vertical distance pivot to bob is cos 35 = 0.819

At the lowest point, vertical distance is 1.0, so the change is the difference, 0.181 meter

The potential energy of that height is converted to kinetic energy of motion, which determines the speed.

PE = KE

mgh = ½mV²

V = √(2gh) = 1.88 m/s

onyebuchinnaji

The speed of the suspended mass at the bottom of the swing is 2.83 m/s.

Speed of the pendulum at bottom

The speed of the pendulum at the bottom of the swing is calculated by applying the principle of conservation of energy as follows;

K.E = P.E

where;

  • K.E is the kinetic energy
  • P.E is the potential energy

[tex]\frac{1}{2} mv^2 = mgh\\\\\frac{1}{2} mv^2 = mg\times lcos(\theta)\\\\v^2 = glcos(\theta)\\\\v = \sqrt{glcos(\theta)} \\\\v = \sqrt{9.8 \times 1 \times cos(35)} \\\\v = 2.83 \ m/s[/tex]

Thus, the speed of the suspended mass at the bottom of the swing is 2.83 m/s.

Learn more about conservation of energy here: https://brainly.com/question/166559

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