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A large flagpole stands outside of an office building. Marquis realizes that when he looks up from the ground 60m away from the flagpole, the top of the flagpole and the top of the building line up. If the flagpole is 35m tall and Marquis is 170m from the building, how tall is the building?

Answer :

Answer:

99.17m

Step-by-step explanation:

In the diagram, Marquis is at Point A and the flag pole is length DE, the building is of length BC.

Triangles ADE and ABC are therefore similar right triangles.

Applying this,

[TeX]\frac{|DE|}{|AE|}=\frac{|BC|}{|AC|}[/TeX]

[TeX]\frac{35}{60}=\frac{|BC|}{170}[/TeX]

|BC|=170*35÷60

|BC|=99.17m

${teks-lihat-gambar} Newton9022
MrRoyal

The height of the office building is 99.2 meters

The given parameters are:

  • d1: The flagpole's distance from the office building = 60 m
  • d2: Marquis' distance from the office building = 170 m
  • h1: Height of the flagpole = 35 m

The above parameters can be represented using the following equivalent ratio

[tex]h1 : d1 = h2 : d2[/tex]

Express as fraction

[tex]\frac{h1 }{ d1} = \frac{h2 }{ d2}[/tex]

So, we have:

[tex]\frac{35}{60}=\frac{h2}{170}[/tex]

Multiply both sides by 170

[tex]170 \times \frac{35}{60}=h2[/tex]

[tex]99.2=h2[/tex]

Rewrite as:

[tex]h2 =99.2[/tex]

Hence, the building is 99.2 meters tall

Read more about equivalent ratios at:

https://brainly.com/question/2328454

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