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You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between your feet and the ice. A friend throws you a 0.400-kg ball that is traveling horizontally at 10.0 m/s. Your mass is 75.0 kg.

(a) If you catch the ball, with what speed do you and the ball move afterward?

(b) If the ball hits you and bounces off your chest, so afterward it is moving horizontally at 8.0 m/s in the opposite direction, what is your speed after the collision?

Answer :

Answer:

(a). The speed by which ball move afterwards [tex]V_2[/tex] = 0.0533 [tex]\frac{m}{s}[/tex]

(b). The speed of ball after collision [tex]V_2[/tex] = 0.096 [tex]\frac{m}{s}[/tex]

Explanation:

Given data

[tex]m_1[/tex] = 0.4 kg

Velocity [tex]V_1[/tex] = 10 [tex]\frac{m}{s}[/tex]

[tex]m_2[/tex] = 75 + 0.4 = 75.04 kg

(a). From conservation of momentum principal

[tex]m_1[/tex] [tex]V_1[/tex] = [tex]m_2[/tex] [tex]V_2[/tex]

0.4 × 10 = 75.04 × [tex]V_2[/tex]

[tex]V_2[/tex] = 0.0533 [tex]\frac{m}{s}[/tex]

This is the speed by which ball move afterwards.

(b). Again from conservation of momentum principal

0.4 × 10 = - 0.4 × 8 + 75 × [tex]V_2[/tex]

[tex]V_2[/tex] = 0.096 [tex]\frac{m}{s}[/tex]

This is the speed of ball after collision.

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