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If the coefficient of static friction between your coffee cup and the horizontal dashboard of your car is µs = 0.800, how fast can you drive on a horizontal roadway around a right turn of radius 28.0 m before the cup starts to slide?

Answer :

Answer:

Before start of slide velocity will be 14.81 m/sec

Explanation:

We have given coefficient of static friction [tex]\mu =0.8[/tex]

Angle of inclination is equal to [tex]\Theta =tan^{-1}\mu[/tex]

[tex]\Theta =tan^{-1}0.8=38.65^{\circ}[/tex]

[tex]tan{38.65^{\circ}}=0.8[/tex]

Radius is given r = 28 m

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

We know that [tex]tan\Theta =\frac{v^2}{rg}[/tex]

[tex]0.8=\frac{v^2}{28\times 9.8}[/tex]

[tex]v^2=219.52[/tex]

[tex]v=14.816m/sec[/tex]

So before start of slide velocity will be 14.81 m/sec

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