Answered

A bag contains 10 red marbles, 15 yellow marbles, 5 green marbles, and 20 blue marbles. Five marbles are drawn from the
bag.
What is the approximate probability that exactly two of the five are blue?

Answer :

The approximate probability that exactly two of the five are blue is 0.3641

Step-by-step explanation:

Step 1

The total marble in the bag are [tex](10+15+5+20)=50[/tex]

  • The probability of drawing red marble is =[tex]\frac{10}{50}[/tex]=1/5
  • The probability of drawing yellow marble is =[tex]\frac{15}{50}[/tex]=3/10
  • The probability of drawing green marble is =[tex]\frac{5}{10}[/tex]=1/10
  • The probability of blue marble is =[tex]\frac{20}{50}[/tex]=2/5

Step 2

When five marbles are drawn from the bag, we have to find the probability that exactly two of the five are blue.

=Probability that 2 blue marbles and 3 non blue marbles

Step 3

2 marbles should be drawn out of the 20 blue marbles and 3 non blue marbles out of 30 marbles

No of ways = [tex]20C2(30C3)[/tex]

Total no of ways of drawing 5 marbles = [tex]50C3[/tex]

Probability=[tex]20C2(30C3)/50C5=190(4060)/2118760=0.3641[/tex]

Step 4

The approximate probability that exactly two of the five are blue is 0.3641

Answer:

the answer is nothing short of 36%

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