Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be parallel, they need to have the same slope.
y - 3x = 2 Add 3x on both sides to change the equation to slope-intercept form
y - 3x + 3x = 2 + 3x
y = 3x + 2 The slope is 3, so the parallel line's slope is also 3.
Now that you know the slope, substitute/plug it into the equation
y = mx + b
y = 3x + b To find "b", plug in the point (6, 1) into the equation, then isolate/get the variable "b" by itself
1 = 3(6) + b
1 = 18 + b Subtract 18 on both sides to get "b" by itself
1 - 18 = 18 - 18 + b
-17 = b
y = 3x - 17 Your answer is the 1st option
Answer:
y=3x-17
Step-by-step explanation:
You first get y by its and you do this by adding 3x to both sides of the equal sign. You should then get y=3x+2 and then to find the parallel line, the x should stay the same as the first equation so that takes out the -3x. Then you continue to draw the line down until you get a y-intercept which turns out to be 17. You also know that the y-intercept is going to be negative so that takes out the two 19's.