Answer :
Answer:
The Net reaction is
- [tex]H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction[/tex]
- [tex]H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH[/tex]
- [tex]HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH[/tex]
Explanation:
From the Question we are told that the buffers are
[tex]H_2C_6H_5O_7^ -[/tex] and [tex]HC_6H_5O_7 ^{ 2-}[/tex]
When NaOH is added the Net ionic reaction would be
- [tex]H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction[/tex]
- [tex]H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH[/tex]
- [tex]HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH[/tex]
Answer:
Net ionic equation are as follows
[tex](1) H_3C_6H_5O_7 + 0H^- \rightarrow H_2C_6H_5O_7^- +H_2O \\\\ (2) H_2C_6H_5O_7^ - + OH^- \rightarrow H_C_6H_5O_7^{ 2-} + H_2O \\\\ (3) HC_6H_5O_7 ^{2-} + OH^- \rightarrow C_6H_5O_7^{3-} +H_2O[/tex]
Explanation:
Citric acid, H3C6H5O7, is a triprotic acid
he net ionic equation for the reaction that occurs when NaOH is added to a buffer containing H2C6H5O7 - and HC6H5O7 2-
Net ionic equation are as follows
[tex](1) H_3C_6H_5O_7 + 0H^- \rightarrow H_2C_6H_5O_7^- +H_2O \\\\ (2) H_2C_6H_5O_7^ - + OH^- \rightarrow H_C_6H_5O_7^{ 2-} + H_2O \\\\ (3) HC_6H_5O_7 ^{2-} + OH^- \rightarrow C_6H_5O_7^{3-} +H_2O[/tex]