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g Problem 5. A 100 g firecracker is launched vertically into the air and explodes into two pieces at the peak of its trajectory. If a 72 g piece is projected horizontally to the left at 20 m/s, what is the speed and direction of the other piece

Answer :

Answer:

Explanation:

At the peak , velocity of firecracker = 0

It splits into mass of m₁ = 72 g and m₂ = 28 g

Applying conservation of momentum laws

m₁ v₁ = m₂v₂

72 x 20 = 28 x v₂

v₂ = 51.43 m / s .

It will go opposite to  other piece to conserve momentum ie to the right direction.

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