Suppose a water tank in the shape of a right circular cylinder is thirty feet high and eight feet in diameter. a) How much sheet metal was used in its construction of the whole water tank? Round to the nearest hundredth.

Answer :

Answer:

[tex]755.98 ft^2[/tex]

Step-by-step explanation:

Height of the Cylinder= 30 feet

Diameter = 8 feet

Radius= Diameter/2 = 8/2 = 4 feet

The Amount of Metal Sheet used in constructing the tank is the Total  Surface Area of the Tank.

Total Surface Area of a Cylinder =

[tex]=2\pi r(r+h)\\=2*\pi*4(4+30)\\=8*\pi*30=\\=240\pi\\=755.98 ft^2[/tex]

     Metal sheet used to construct a right circular cylinder will be 854.51 square feet.

Total surface area of a right cylinder:

  • Total surface area of a right cylinder is given by the expression,

        Total surface area = [tex]2\pi r(r+h)[/tex]

        Here, [tex]r=[/tex] Radius of the cylinder

        [tex]h=[/tex] Height of the cylinder

Given in the question,

  • A right cylinder with radius 'r' = [tex]\frac{8}{2}=4[/tex] feet

        Height of the cylinder 'h' = 30 feet

Since, metal sheet required for the cylinder = Surface area of the cylinder

Substitute these values in the expression for "total surface area",

Total surface area = [tex]2\pi(4)(4+30)[/tex]

                              = [tex]272\pi[/tex]

                              = 854.513

                              = 854.51 square feet

          Therefore, metal sheet used to construct the water tank will be 854.51 square feet.

Learn more about the surface area of a cylinder here,

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