Answer:
[tex]a= 0.2 m/s^2\\s = 20m\\t = 2 s[/tex]
Explanation:
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two forces are given
[tex]f_{1} = 2000 N \\f_{2} = 1800 N\\F_{net} = 2000 -1800 = 200N[/tex]
A) (a) What is the acceleration of the 1000-kg boat?
[tex]f_{net} = ma\\a = \frac{f_{net}}{m}[/tex]
[tex]a = \frac{200}{1000}\\a= 0.2 m/s^2[/tex]
B) If it starts from rest, how far will it move in 10.0 s?
using kinematic equation
[tex]s = ut +\frac{1}{2}at^2\\ u = 0 \ m/s\\\\S = \frac{1}{2} at^2 \\s = \frac{1}{2} \times 0.2 \times (10)^2\\s = 10 m[/tex]
(c) What will its velocity be at the end of this time?
[tex]v= u +at \\u = 0 m/s \\v = 0.2\times 10\\v = 2 m/s[/tex]
