Answer :
Answer:
[tex]T_{final} =45.64C[/tex]=final temperature
Explanation:
In the question specific heat of water is not given but we should know the value of that and it 4.18Jg∘C
Specific heat means how much heat is required to increase the temperature of 1 gram of substance that substance by 1∘C .
Equation between heat lost or gain and the change in temperature.
q=m⋅c⋅ΔT , where
q - the amount of heat
m - the mass of the sample
c - specific heat of sample
ΔT - change in temperature
put all the given value into this ,
[tex]q=m\times c \times \Delta T[/tex]
[tex]\Delta T=\frac{q}{mc} =\frac{1962}{732 \times 4.18}[/tex]
[tex]\Delta T= 0.64C[/tex]
[tex]T_{final} -T_{initial} =0.64C[/tex]
[tex]T_{final} =45.64C[/tex]=final temperature.