Answer :
12 + 0.15m = 10 + 0.25m
0.15m - 0.25m = 10 - 12
- 0.10m = -2
m = -2/-0.10
m = 20
At 20 miles, the cost of the two taxi services will be the same.
0.15m - 0.25m = 10 - 12
- 0.10m = -2
m = -2/-0.10
m = 20
At 20 miles, the cost of the two taxi services will be the same.
Answer:
20 miles.
Step-by-step explanation:
Let m be the miles traveled by the both Taxi.
Pick up charge of A-1 taxi = $12
Cost of travelling 1 mile = $0.15
Cost of travelling x mile = $0.15x
So, total cost of A-1 taxi = [tex]12+0.15x[/tex] --A
Pick up charge of Z-6 taxi = $10
Cost of travelling 1 mile = $0.25
Cost of travelling x mile = $0.25x
So, total cost of Z-6 taxi = [tex]10+0.25x[/tex] --B
Now we are supposed to find At what mileage is the cost for both taxi services the same.
So, equate 1 and 2
[tex]12+0.15x=10+0.25x[/tex]
[tex]12-10=0.25x-0.15x[/tex]
[tex]2=0.10x[/tex]
[tex]\frac{2}{0.10}=x[/tex]
[tex]20=x[/tex]
So, the cost for both taxi services will be same at 20 miles.