Answer :
[tex]\dfrac{\displaystyle\binom{8}{2}}{\displaystyle\binom{12}{2}}=\\\\
\dfrac{\dfrac{8!}{2!6!}}{\dfrac{12!}{2!10!}}=\\\\\
\dfrac{8!}{2!6!}\cdot\dfrac{2!10!}{12!}=\\\\
\dfrac{7\cdot8}{2}\cdot\dfrac{2}{11\cdot12}=\\\\
\dfrac{7\cdot4}{11\cdot3}=\\\\
\dfrac{28}{33}
[/tex]