Answer :
Answer:
The equation of ellipse centered at the origin
[tex]\frac{x^2}{18} +\frac{y^2}{10} =1[/tex]
Step-by-step explanation:
given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)
The foci are (-C,0) and (C ,0)
Given data (±√8,0)
the focus has x-coordinates so the focus is lie on x- axis.
The major axis also lie on x-axis
The minor axis lies on y-axis so c0-vertices are (0,±√10)
given focus C = ae = √8
Given co-vertices ( minor axis) (0,±b) = (0,±√10)
b= √10
The relation between the focus and semi major axes and semi minor axes are [tex]c^2=a^2-b^2[/tex]
[tex]a^{2} = c^{2} +b^{2}[/tex]
[tex]a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}[/tex]
[tex]a^{2} =18[/tex]
[tex]a=\sqrt{18}[/tex]
The equation of ellipse formula
[tex]\frac{x^2}{a^2} +\frac{y^2}{b^2} =1[/tex]
we know that [tex]a=\sqrt{18} and b=\sqrt{10}[/tex]
Final answer:-
The equation of ellipse centered at the origin
[tex]\frac{x^2}{18} +\frac{y^2}{10} =1[/tex]
Answer: (x^2/25)+(y^2/16)=1
Step-by-step explanation:just trust me, I got the answer from khan academy and the other answer is wronggggg DO YOU UNDERSTAND?? THE OTHER ANSWER IS WRONG