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"If the resistance in a constant voltage circuit is doubled, the power dissipated by this circuit will Question 12 options: decrease to one-half its original value. decrease to one-fourth its original value. increase by a factor of two. increase by a factor of four."

Answer :

Answer:

Explanation:

let resistance = R and power = P

power dissipated in the circuit, P = V² / R

let the new resistance = 2 R

then new power P₁ = V² / 2 R = 1/2 ( V² / R) = [tex]\frac{1}{2}[/tex] P

therefore the power dissipated by this circuit will decrease to one-half its original value

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