Answer:
The product of given expression [tex]\left(3x-7y\right)^2[/tex] is [tex]9x^2-42xy+49y^2[/tex]
Step-by-step explanation:
Given : The expression [tex]\left(3x-7y\right)^2[/tex]
We have to find the product of the given expression [tex]\left(3x-7y\right)^2[/tex]
Apply perfect square formula , [tex]\quad \left(a-b\right)^2=a^2-2ab+b^2[/tex]
we have a = 3x and b = 7y
we get,
[tex]=\left(3x\right)^2-2\cdot \:3x\cdot \:7y+\left(7y\right)^2[/tex]
Simplify, we have,
[tex]=9x^2-42xy+49y^2[/tex]
Thus, The product of given expression [tex]\left(3x-7y\right)^2[/tex] is [tex]9x^2-42xy+49y^2[/tex]
