Answer:
The probability of choosing 2 red balls and then 1 green ball is:
225/2744
Step-by-step explanation:
There are 5 red and 9 green balls in a bag.
Total balls=5+9=14
We randomly choose balls one at a time, with replacement.
(we draw a ball, look at it and place it in the bag and then draw another one)
P(choosing 2 red balls and then 1 green ball)
= [tex]\dfrac{5}{14}\times \dfrac{5}{14}\times \dfrac{9}{14}[/tex]
= 225/2744
Hence, the probability of choosing 2 red balls and then 1 green ball is:
225/2744
