Answer :
Answer:
n = 8
Step-by-step explanation:
Using the rule of exponents
[tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]
Given
[tex](9)^{2n-1}[/tex] = [tex](27)^{n+2}[/tex], then
[tex](3^2)^{2n-1}[/tex] = [tex](3^3)^{n+2}[/tex]
[tex]3^{4n-2}[/tex] = [tex]3^{3n+6}[/tex]
Since the bases on both sides are equal, both 3 then equate the exponents
4n - 2 = 3n + 6 ( subtract 3n from both sides )
n - 2 = 6 ( add 2 to both sides )
n = 8
Answer:
n = 8
Step-by-step explanation:
9²ⁿ⁻¹ = 27ⁿ⁺²
(3²)²ⁿ⁻¹ = (3³)ⁿ⁺²
3⁴ⁿ⁻² = 3³ⁿ⁺⁶
4n - 2 = 3n + 6
4n - 3n = 6 + 2
n = 8