Answer :
Answer:
a. the frequency of the record player
f = 1.3 rev per second = 1.3 Hz
b. the period of the record player.
T = 0.77 seconds
Explanation:
Given;
Speed of record player v = 78 rpm
a) frequency of the record player is the number of revolutions the record player makes per second.
f = 78 rev/minute = 78/60sec = 1.3 rev per second
f = 1.3 Hz
b) period of the record player is the amount of time needed by the record player to complete one revolution.
T = 1/f (or 60s/78rev = 0.77 s)
T = 1/1.3
T = 0.77 seconds
Answer:
(a) The frequency of the record player is 1.3 Hz
(b) The period of the record player is 0.77 s
Explanation:
Given number of revolution per minute = 78 RPM
Part (a) the frequency of the record player
One revolution per minute, 1 RPM = ¹/₆₀ Hz
78 RPM = ?
Thus, 78 RPM = 78 ( ¹/₆₀ HZ) = 1.3 Hz
The frequency of the record player is 1.3 Hz
Part (b) the period of the record player
Period is inverse of frequency
T = 1 / f
T = 1 / 1.3 Hz
T = 0.77 s
The period of the record player is 0.77 s