Answer :
Answer: x=10 and x= 3.66667
Step-by-step explanation:
you would need to at 110 to both side to get c before you can solve the quadratic formula, once you have done that you should get 3x2-41x+110=0 than you can now put it in to the formula(-b[tex]\frac{-b(+-)\sqrt{b^{2-4ac} } }{2a}[/tex]) which will now be [tex]\frac{-(-41)(+-)\sqrt{41^{2-4(3)(110)} } }{2(3)}[/tex] than solve [tex]\frac{41(+-)\sqrt{1681-1320} }{6}[/tex] now combined to get [tex]\frac{41(+-)\sqrt{361} }{6}[/tex] the discriminant [tex]b^{2}[/tex]-4sc > 0 so there are two real roots which are, [tex]x= \frac{41(+-) 19}{6}[/tex] simplify the radicals, x [tex]\frac{60}{6}[/tex]= and x = [tex]\frac{22 }{6}[/tex] that will turn into x = 10 and x= 3.66667