Answer :
Answer:
Given Data:
mass of solute= 0.2
volume of solution: 250ml
Normality=?
Explanation:
250ml =0.25dm3 Volume
m.mass of NaOH= 40g/mol
Equivalent weight of solute=40/1 =40
N=mass in g of solute/equivalent weight of solute*Volume of solution
N=0.2/40*0.25
N= 0.02
The normality of NaOH solution should be 0.02.
Calculation of the normality of NaOH solution:
Since
mass of solute= 0.2
volume of solution: 250ml
So, here
250ml =0.25dm3 = Volume
m.mass of NaOH= 40g/mol
Now
Equivalent weight of solute=40/1 =40
So, the normality should be
N=mass in g of solute/equivalent weight of solute*Volume of solution
N=0.2/40*0.25
N= 0.02
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