DummyC
Answered

Find the domain of
[tex]y = \sqrt{x + 6} [/tex]
A. x ≥ -1/6

B. x > 6

C. x ≥ -6

D. x ≥ 6​

Answer :

Answer:

C (x ≥ -6)

Step-by-step explanation:

Algebraic:

The domain of [tex]\sqrt{x}[/tex] is [tex]x\geq 0[/tex]. When transformed 6 units to the left, it becomes [tex]x\geq -6[/tex]

Graphically:

As shown in the attached graph, [tex]x\geq -6[/tex] .

${teks-lihat-gambar} jakeob28

Other Questions