Answer :

dalendrk
[tex](10+x):(y-3)=\dfrac{10+x}{y-3}[/tex]
calculista

Answer:

[tex]\frac{10+x}{y-3}[/tex]

Step-by-step explanation:

we know that

The expression " [tex]10[/tex] plus x" is equivalent to the algebraic equation

[tex]10+x[/tex]

The expression " y minus [tex]3[/tex]" is equivalent to the algebraic equation

[tex]y-3[/tex]

therefore

the complete expression " the quotient of [tex]10[/tex] plus x and y minus [tex]3[/tex]" is equivalent to the algebraic equation

[tex]\frac{10+x}{y-3}[/tex]

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