Answer:
B) CH3(CH2)10CO2H
Explanation:
Hello,
In this case, we define amphipathic as a compound having both a hydrophilic and a hydrophobic part, for that reason, the hydrophilic part will be water-soluble (polar) whereas the hydrophobic does not (nonpolar). In such a way, some functional groups such as hydroxyl and carboxyl tend to be polar by cause of the presence of O-H bonds whereas long-carboned chains tend to be nonpolar by cause of the presence of C-H and C-C bonds.
Therefore, since A) CH3CH2OH (ethanol) and D) CH3CO2H (acetic acid) are short-carboned chains with polar groups they are largely hydrophilic whereas C) CH3(CH2)10CH3 (dodecane) is highly nonpolar, we sum up that only B) CH3(CH2)10CO2H (dodecanoic acid or lauric acid) is amphoteric as it has a long-charboned part (nonpolar) and a water-soluble part (polar).
Best regards.
The molecule that should be considered as the amphipathic is option B) CH3(CH2)10CO2H.
It is the compound that contains the hydrophilic and the hydrophobic part. Here hydrophobic part it should be considered as the water -soluble i.e. polar while on the other hand, hydrophobic it should not be non-polar. Here we considered the functional groups like hydroxyl and carboxyl that should result in the presence of O-H bonds.
Hence, the option b is correct.
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