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Use graphical approximation techniques or an equation solver to approximate the desired interest rate. A person makes annual payments of $ 1000 into an ordinary annuity. At the end of 5 ​years, the amount in the annuity is $ 5734.70. What annual nominal compounding rate has this annuity​ earned?

Answer :

Answer:

Annual Compounding rate is approximately 6.85%

Explanation:

The future value of an ordinary annuity with deposits P made  for n years, with interest compounded times once a year at an annual rate i, is given as:

[tex]F.V.=\dfrac{P[(1+i)^n-1]}{i}[/tex]

If Future Value = $5734.70.

Regular Deposit, P=$1000

n=5 years

[tex]5734.70=\dfrac{1000[(1+i)^5-1]}{i}[/tex]

Using Excel:

In put this formula in Cell B2 : =(1000*(1+A2)^5-1000)/A2

We find out that our interest rate, r is between 0.05 and 0.06

Taking Intermediate values, [tex]r\approx 0.0685[/tex]

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