Answer :
Answer:
(a) 32.5 kgm/s
(b) 32.5 Ns
(c) 10.8 N
Explanation:
The change in momentum can be calculated from the definition of linear momentum:
[tex]\Delta p=\Delta (mv)= m \Delta v\\\\\Delta p= (5.00kg)(9.75m/s-3.25m/s)\\\\\Delta p=32.5kgm/s[/tex]
Then, the change in momentum of the body is of 32.5 kgm/s (a).
Now, from the impulse-momentum theorem, we know that the change in momentum of a body [tex]\Delta p[/tex] is equal to the impulse [tex]I[/tex] exerted to it. So, the impulse produced by the force equals 32.5 kgm/s (or 32.5 Ns) (b).
Finally, since we know the value of the impulse and the interval of time, we can easily solve for the magnitude of the force:
[tex]I=F\Delta t\\\\\implies F=\frac{I}{\Delta t}\\\\F=\frac{32.5Ns}{3.0s}\\\\F=10.8N[/tex]
It means that the magnitude of the force is of 10.8N (c).
Answer:
(a) the change in momentum of the body is 32.5 kg.m/s
(b) the impulse produced by the force is 32.5 N.s
(c) the magnitude of the force is 10.83 N
Explanation:
Given;
mass of the body, m = 5.00-kg
initial velocity of the body, u = 3.25 m/s
final velocity of the body, v = 9.75 m/s
time taken, t = 3.0 seconds
Part (a) the change in momentum of the body
ΔP = mv - mu
= (5 x 9.75) - (5 x 3.25)
= 48.75 - 16.25
= 32.5 kg.m/s
Part (b) the impulse produced by the force
I = f x t
where;
I is impulse
f is the applied force
t is time
f x t = mΔv
I = mΔv
I = m (v -u)
I = 5 (9.75 - 3.25)
I = 32.5 N.s
Part (c) the magnitude of the force;
I = f x t
f = I / t
where;
f is magnitude of the force.
I is impulse
t is time
f = 32.5 / 3
f = 10.83 N