TheReginator
Answered

Choose one of the factors of x3 − 1331

x-11 (I'm pretty sure its this one but I'm just checking)

x2-11x+121

x2+22x+121

none of the above

Answer :

caylus
Hello,

[tex]a^3-b^3=(a-b)(a^2+ab+b^2)\\ Here\ a=x \ and \ b=11 [/tex]

x^3-11^3=(x-11)(x²+11x+121)
Answer A
I haven't read the question : x-11 is a factor! sorry.
frika

Use formula for difference of perfect cubes:

[tex]a^3-b^3=(a-b)(a^2+ab+b^2).[/tex]

Consider expression [tex]x^3-1331.[/tex] You know that [tex]1331=11^3,[/tex] then

[tex]x^3-1331=x^3-11^3=(x-11)(x^2+11x+121).[/tex]

The quadratic trinomial [tex]x^2+11x+121[/tex] cannot be factored anymore, so the expression [tex]x^3-1331[/tex] has two factors [tex]x-11[/tex] and  [tex]x^2+11x+121.[/tex]

Answer: correct choice is A.

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