Answer :
Answer:
The mass of iron produced is 44.29 grams
Explanation:
Al + FeO3 [tex]\rightarrow[/tex]
Aluminium + Iron III oxide
2Al + F₂O₃ → Al₂O₃ + 2Fe
Molar mass of Al = 26.981539 g/mol
Molar mass of F₂O₃ = 159.69 g/mol
Number of moles of Aluminium = 21.4 g/26.981539 g/mol = 0.7931 moles
Number of moles of F₂O₃ = 91.3 g/159.69 g/mol = 0.572 moles
Hence, 1 mole of Al combines with 1/2 moles of F₂O₃, 0.7931 moles of Al will combine with 0.7931 × 1/2 or 0.3966 moles of F₂O₃ to produce 0.7931 moles of iron
Molar mass of iron = 55.845 g/mol
Therefore the mass of iron produced = Number of moles × Molar mass = 0.7931 × 55.845 = 44.29 grams.