Answer :
Answer:
0.52rad/s^2
Explanation:
To find the angular acceleration you use the following formula:
[tex]\omega^2=\omega_o^2+2\alpha\theta[/tex] (1)
w: final angular velocity
wo: initial angular velocity
θ: revolutions
α: angular acceleration
you replace the values of the parameters in (1) and calculate α:
[tex]\alpha=\frac{\omega^2-\omega_o^2}{2\theta}[/tex]
you use that θ=22 rev = 22(2π) = 44π
[tex]\alpha=\frac{(12rad/s)^2-(0rad/s)^2}{2(44\pi)}=0.52\frac{rad}{s^2}[/tex]
hence, the angular acceñeration is 0.52rad/s^2