Answer:
121 degrees C
Explanation:
The units for this problem could all be plugged into the equation q=MC delta T, while you solve for T-final.
18000 J=(150.0 g)(4.184 J/g C)(T-final - 92.0 C)
Since in the problem your q value is identified with the units kJ, you would have to convert it to J so it would work with the specific heat capacity's units that were Joules, Grams, and Celsius.
Next, you would multiply your grams and specific heat capacity together:
18000 J=(627.6)(T-final - 92.0 C)
Then you would divide 627.6 to 18000:
28.7 = T-final - 92.0 C
Finally, you would add 92 C to get your T-final answer:
120.7 C = T-final
But since your answer needs to be in 3 sig figs, your actual answer would be 121 C
I hope this helps!
