Will mark brainiest please help me in this question im stuck.

Answer:
A
Step-by-step explanation:
First, we need to find the slope of QP.
The slope formula is:
[tex]m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
We can call Q (-6,10) our "1" coordinate, and P(-12, -2) our "2" coordinate. Therefore, -6 is x1, 10 is y1, -12 is x1 and -2 is y2.
[tex]m=\frac{-2-10}{-12- -6}[/tex]
[tex]m=\frac{-12}{-6}[/tex]
m=2
Now we need to find the slope perpendicular to QP.
QP has a slope of 2. Perpendicular lines have negative reciprocal slopes.
Negate:
2--> -2
Reciprocal (flip numerator:top number and denominator: bottom number)
-2/1--> -1/2
So, the answer is A