Answer :
If you would like to find the value of y for x = 2, you can do this using the following steps:
y = 4 * x + 2 * x^2 – x^3
x = 2
y = 4 * 2 + 2 * 2^2 - 2^3 = 8 + 2 * 4 - 8 = 8 + 8 - 8 = 8
The correct result would be y = 8.
y = 4 * x + 2 * x^2 – x^3
x = 2
y = 4 * 2 + 2 * 2^2 - 2^3 = 8 + 2 * 4 - 8 = 8 + 8 - 8 = 8
The correct result would be y = 8.
[tex]Start \ with \ the \ original \ equation [/tex]
[tex]y=4x+2x^2-x*3[/tex]
[tex]Let \ x=2[/tex]
[tex]y=4*2+2*2^2-2*3[/tex]
[tex]\fbox{y = 10}[/tex]
[tex]y=4x+2x^2-x*3[/tex]
[tex]Let \ x=2[/tex]
[tex]y=4*2+2*2^2-2*3[/tex]
[tex]\fbox{y = 10}[/tex]