1. A student tried to solve the following problem by selecting the tile as shown. What, if anything, did the student do wrong?
2AgNO3 (aq) + Cu (s) + 2Ag (s) + Cu(NO3)2 (aq)
How many moles of silver nitrate (AgNO3) are
needed to produce 6.75 moles of copper (II) nitrate
(Cu(NO3)2) upon reacting with excess copper (Cu)?
6.75 mol Cu(NO3)2
1 mol Cu(NO3)2
2 mol AgNO3
O A. The student chose the wrong tile to solve the problem
O B. The student chose the correct tile, but needs to flip the tile to make the units cancel
C. The student chose the correct tile, but needs to add a second tile to finish the solution.
D. There is nothing wrong. The problem is ready to be solved.

Answer :

Answer:

B. The student chose the correct tile, but needs to flip the tile to make the units cancel

Explanation:

Based on the reaction:

2AgNO₃(aq) + Cu(s) → 2Ag(s) + Cu(NO₃)₂ (aq)

2 moles of AgNO₃ react per mole of Cu producing 2 moles of Ag and 1 mole of Cu(NO₃)₂

Thus, if you want to produce 6.75moles of Cu(NO₃)₂ you need:

[tex]6.75moles of Cu(NO_3)_2 \frac{2 mol AgNO_3 }{1 mol Cu(NO_3)_2}[/tex] = 13.50 moles of AgNO₃ are needed

Thus, if you analize the tile shown by the student:

B. The student chose the correct tile, but needs to flip the tile to make the units cancel

The amount of silver nitrate that has been used for producing 6.75 mol of cupric nitrate has been 13.75 mol. The student chooses the right tile, but the tile has to be flipped in order to cancel the units. Thus. option B is correct.

The balanced chemical equation for the reaction has been:

[tex]\rm 2\;AgNO_3\;+\;Cu\;\rightarrow\;2\;Ag\;+\;Cu(NO_3)_2[/tex]

According to the balanced chemical equation, 2 moles of silver chloride have been required to produce 1 mole of cupric nitrate.

The amount of silver nitrate that has been  required to produce 6.75 moles of cupric nitrate has been:

1-mole cupric nitrate = 2moles silver  nitrate

6.75 moles cupric nitrate = 6.75 × 2 moles silver nitrate

6.75 moles cupric nitrate = 13.5 moles silver nitrate.

The amount of silver nitrate that has been used for producing 6.75 mol of cupric nitrate has been 13.75 mol.

The student chooses the right tile for the determination of the solution to the problem, but the tile has to be flipped in order to cancel the units. Thus. option B is correct.

For more information about the moles of product, refer to the link:

https://brainly.com/question/4066080

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