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Consider circle A in the diagram below where the m∠DCG=25∘ and mCF^=60∘ and prove that m∠EDF=55∘.

Given that m∠DCG=25∘, this angle intercepts arc DG^ which makes mDG^=_, this means that mED^=130∘ as EG^ is a diameter.

∠CED intercepts CFD^, which makes m∠CED=_.

∠ECD intercepts ED^ which makes m∠ECD=_.

∠CDF intercepts CF^ which is 60∘, making m∠CDF=30∘. Using the triangle sum theorem, m∠EDC=_, and using Angle addition postulate the m∠EDF=55∘.

Consider circle A in the diagram below where the m∠DCG=25∘ and mCF^=60∘ and prove that m∠EDF=55∘. Given that m∠DCG=25∘, this angle intercepts arc DG^ which make class=

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50, 90, 65, 25

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I dont know how to get to it that is why I searched it up :/

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