magsjenny
Answered

at what distance of separation, or, must two 5.87*10^-8 coulomb charges be positioned in order for the repulsive force between them to be 64.9 N?

Answer with work shown in GUESS format

G (givens)
U (unknown)
S (substitute)
S (solve)

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Answer :

917006450984help

Explanation:

r^2= 9×10^9 × 5.87×5.87×10^-16 / 64.9

=47.7× 10^-8

so taking sq. root

r = 6.9 ×10^-4 m

or

r= 6.9×10^ -2 cm

this gives the required seperation

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