The following balls are placed in an urn: 4 red, 2 yellow, 4 blue, and 2 green. One ball is randomly drawn from the urn. What is the probability that the ball
Is either yellow or green?

Answer :

Answer:

1/3 as;

16.66665/100 + 16.66665/100 = 33.33/100

Convert to 12 = 4+4+2 +2 = 4/12

Step-by-step explanation:

or 1/3

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