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The zeros of a parabola are 6 and −5. If (-1, 3) is a point on the graph, which equation can be solved to find the value of a in the equation of the parabola?

3 = a(−1 + 6)(−1 − 5)
3 = a(−1 − 6)(−1 + 5)
−1 = a(3 + 6)(3 − 5)
−1 = a(3 − 6)(3 + 5)

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Answer :

Answer:

3 = a(-1 - 6)(-1 + 5).

Step-by-step explanation:

The zeroes are 6 and  -5  so we can write it as

y = a(x - 6)(x + 5)

Now the point (-1, 3) is on the line so substituting for x and y:

3 = a(-1 - 6)(-1 + 5).

3 = a(-1 - 6)(-1 + 5) can be solved to find the value of a in the equation of the parabola. Option b is correct.

The zeros of a parabola are 6 and −5. If (-1, 3) is a point on the graph,
The equation to be determined.


What is a parabola?

A parabola is a cross section cut out of the cone and represented by an equation y = 4ax^2

The zeroes of a parabola are 6 and  -5.
Equation of parabola in zero form equation
y = a ( x - A ) ( x - B )    (where A = 6 and B = -5)
y = a ( x - 6 ) ( x + 5 )   - - - - - - - (1)

Now, Point ( -1 , 3  ) lies on the parabola, so put these points in equation 1 in order to find the value of a

3 = a(-1 - 6)(-1 + 5)


Thus, 3 = a(-1 - 6)(-1 + 5) can be solved to find the value of a in the equation of the parabola.

Learn more about parabola here:

brainly.com/question/4074088

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