Answer :
Answer:
~1.82381
Explanation:
Since it dissociates in water there will be equally amounts of H and NO3. Therefore, there will be 0.0150 M H+ ions. Simply take the -log(H+) = pH, so -log(0.0150) = ~1.82
The pH of the given solution when HNO3 dissociates completely in water is 1.82381.
Calculation of the pH:
Since it is the 0.0150 M HNO3 solution. Also we assume that HNO3
dissociates completely in water. So there should be equivalent amount of H and NO3.
So, it can be like
-log(H+) = pH,
so -log(0.0150)
= 1.82
Hence, we can conclude that The pH of the given solution is 1.82381.
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