Answer :
Question:
Vincent bought a 25-pound bag of rice. He cooked 6.25 pounds of the rice. He stored the rest of the rice in [tex]3\frac{3}{4}[/tex] - pound portions. What is the maximum number of [tex]3\frac{3}{4}[/tex] - pound portions he stored?
Answer:
The maximum number of portion he stored is 5 portion
Step-by-step explanation:
Given
Size of Rice = 25 lb
Size of Cooked Rice = 6.25 lb
Portions saved = [tex]3\frac{3}{4}[/tex] lb
Required
Number of portion saved;
First, the size of rice after cooking needs to be calculated;
If 6.25lb of rice was cooked from a total of 25lb;
Then, the size of rice left is
[tex]Size = 25lb - 6.25lb[/tex]
[tex]Size = 18.75lb[/tex]
Now that we have the amount left after cooking; we can simply calculate the maximum number of portions;
This is calculated by dividing size of rice left by portions of saved rice;
i.e.
Maximum number of portion = Size of rice left / Portions of saved rice
Maximum number of portion = [tex]\frac{18.75lb}{3\frac{3}{4}lb}[/tex]
Convert [tex]3\frac{3}{4}[/tex] to mixed fraction
Maximum number of portion = [tex]\frac{18.75lb}{\frac{15}{4}lb}[/tex]
Maximum number of portion = [tex]\frac{18.75}{\frac{15}{4}}[/tex]
Rewrite expression
Maximum number of portion = [tex]18.75 / \frac{15}{4}[/tex]
Change divide (/) sign to multiplication (*)
Maximum number of portion = [tex]18.75 * \frac{4}{15}[/tex]
Maximum number of portion = [tex]\frac{75}{15}[/tex]
Maximum number of portion = 5
Hence, the maximum number of portion he stored is 5 portions