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Which expression is equivalent to log Subscript 12 Baseline StartFraction x Superscript 4 Baseline StartRoot x cubed minus 2 EndRoot Over (x + 1) Superscript 5 Baseline EndFraction?

4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x times 1)


4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline StartFraction x cubed Over 2 EndFraction minus 5 log Subscript 12 Baseline 1


log Subscript 12 Baseline 4 x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x) + 1


4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x + 1)

Answer :

Answer:

(D)[tex]4log_{12}x+\frac{1}{2} log_{12}(x^3-2)-5log_{12}(x+1)[/tex]

4 log Subscript 12 Baseline x + one-half log Subscript 12 Baseline (x cubed minus 2) minus 5 log Subscript 12 Baseline (x + 1)

Step-by-step explanation:

Given the expression:

[tex]log_{12}\dfrac{x^4\sqrt{x^3-2} }{(x+1)^5}[/tex]

We first apply the division law of logarithm:[tex]log_{a}x/y=log_{a}x-log_{a}y[/tex]

[tex]log_{12}\dfrac{x^4\sqrt{x^3-2} }{(x+1)^5}=log_{12}x^4\sqrt{x^3-2}-log_{12}(x+1)^5[/tex]

Next, by addition law: [tex]log_{a}xy=log_{a}x+log_{a}y[/tex]

[tex]=log_{12}x^4+log_{12}\sqrt{x^3-2}-log_{12}(x+1)^5\\\\Log a^m=mLog a, Log \sqrt{x}=log x^{1/2}\\\\ =4log_{12}x+log_{12}(x^3-2)^{1/2}-5log_{12}(x+1)\\\\=4log_{12}x+\frac{1}{2} log_{12}(x^3-2)-5log_{12}(x+1)[/tex]

The correct option is D.

Answer

D

 4logw (x^{2} - 6) - 1/3logw (x^{2} + 8)

Step-by-step explanation:

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