Answer:
[tex]\frac{23}{(y-8)(y+8)}=\frac{23}{y^{2}-64}[/tex]
Step-by-step explanation:
[tex]\frac{3y - 1}{(y-8)(y+8)} -\frac{3}{y+8} = \frac{3y - 1}{(y-8)(y+8)} -\frac{3(y-8)}{(y-8)(y+8)} =\\\\=\frac{3y - 1-3y+24}{(y-8)(y+8)} = \frac{23}{(y-8)(y+8)}=\frac{23}{y^{2}-64}[/tex]
