Answer :
Answer:
log3
Step-by-step explanation:
[tex] \frac{1}{3} log8 + log6 - log4 \\ = log {8}^{ \frac{1}{3} } + log( \frac{6}{4} ) \\ = log2 + log( \frac{3}{2} ) \\ = log(2 \times \frac{3}{2} ) \\ = log3[/tex]
Answer:
log3
Step-by-step explanation:
[tex] \frac{1}{3} log8 + log6 - log4 \\ = log {8}^{ \frac{1}{3} } + log( \frac{6}{4} ) \\ = log2 + log( \frac{3}{2} ) \\ = log(2 \times \frac{3}{2} ) \\ = log3[/tex]