Answer :
Answer:
T1 = T2 = 602.33 N
Explanation:
I attached an image of the forces diagram below.
The x component of the forces for this cases is:
[tex]\Sigma F_x=T_1cos\theta-T_2cos\theta=0\\\\T_1cos\theta=T_2cos\theta\\\\T_1=T_2[/tex]
And the y components:
[tex]\Sigma F_y=T_1sin\theta+T_2sin\theta-W=0\\\\T_1=T_2=T\\\\\Sigma F_y=2Tsin\theta=W\\\\T=\frac{W}{2sin\theta}[/tex]
The angle is calculated by using the information about the length of the cable and the vertical distance of the traffic light:
[tex]\theta=tan^{-1}(\frac{1}{15})=3.81\°[/tex]
Thus, you obtain:
[tex]T=\frac{80N}{2(sin3.81\°)}=601.33N[/tex]
hence, the tension in both segments of the cable is 602.33 N