Answer:
Step-by-step explanation:
[tex]Distance=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}} \\[/tex]
A(3,-2) ; B(6,-2)
[tex]AB=\sqrt{(6-3)^{2}+(-2-[-2])^{2}}\\\\ =\sqrt{3^{2}+(-2+2)^{2}}\\\\=\sqrt{9+0}=\sqrt{9}\\\\[/tex]
AB = 3 units
B(6,-2) ; C(6,5)
[tex]BC=\sqrt{(6-6)^{2}+(5-[-2])^{2}} \\\\=\sqrt{0+(5+2)^{2}}\\\\=\sqrt{(7)^{2}}\\[/tex]
BC = 7 units
Area of rectangle = length * width
= AB * BC
= 3 * 7
= 21 square units
