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The manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour. (a-1) At α = .05 in a left-tailed test, would a sample of 16 randomly chosen hours with a mean of 538 and a standard deviation of 50 indicate that the manufacturer’s claim is overstated? Choose the appropriate hypothesis.

Answer :

Answer:

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

Step-by-step explanation:

Explanation:-

Given sample size 'n' =16

Given the manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour.

mean of the Population 'μ' = 560

Mean of the sample Χ⁻ = 538

sample standard deviation' S' = 50

Null hypothesis:H₀:μ > 560

Alternative Hypothesis:H₁ : :μ < 560 (left tailed test)

Test statistic

   [tex]t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }[/tex]

  [tex]t = \frac{538-560 }{\frac{50}{\sqrt{16} } } = -1.76[/tex]

|t| = |-1.76| = 1.76

Degrees of freedom

γ = n-1 =16-1 =15

[tex]t_{\frac{\alpha }{2} } = t_{\frac{0.05}{2} } =t_{0.025} =2.131[/tex]

Conclusion:-

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

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