Four friends were born on consecutive years. The sum of their ages is 62. Let's find the age of the youngest friend: Formula: 4x + 6 = 62 => First is to Subtract 6 from both sides
4x = 56 Then next thing to do is to divide 4 from both sides: => x = 14
14 + 14 + 1 + 14 + 2 + 14 + 3 = 62
62 = 62
Thus the youngest age is 14
