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Calculate the Reynold's number using a viscosity of air as 1.81E-05 kilograms/(meters-seconds), the density of air (see above), the diameter as 0.15 m, and, from the data, 0.89 m/s.

Answer :

lublana

Answer:

8924.6

Explanation:

We are given that

Viscosity of air,[tex]\eta=1.81\times 10^{-5}kg/m-s[/tex]

Density of air,[tex]\rho=1.21kg/m^3[/tex]

Diameter,d=0.15 m

v=0.89m/s

We have to find the Reynold's number.

Reynold's number,R=[tex]\frac{\rho vd}{\eta}[/tex]

Substitute the values then we get

[tex]R=\frac{1.21\times 0.89\times 0.15}{1.81\times 10^{-5}}[/tex]

R=[tex]8924.6[/tex]

Hence, the value of Reynold's number=8924.6

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