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A frequency distribution for the class level of students in an introductory statistics course is shown. Two students are randomly selected without replacement. Complete parts​ (a) through​ (d).
Class
Frequency

Freshman
6
Sophomore
16
Junior
12
Senior
7
a. Determine the probability that the first student obtained is a junior and the second a senior.

Answer :

JeanaShupp

Answer: [tex]\dfrac{21}{410}[/tex].

Step-by-step explanation:

Formula : Probability = [tex]\dfrac{\text{favorable outcomes}}{\text{Total outcomes}}[/tex]

From the given frequency distribution for the class level of students in an introductory statistics course, we have

Number of Junior= 12

Number of Senior = 7

Total students = 6+16+12+7 = 41

Probability that the first student obtained is a junior = [tex]\dfrac{12}{41}[/tex]

Probability that the the second student obtained is a senior. [tex]=\dfrac{7}{41-1}=\dfrac{7}{40}[/tex]

Then, the probability that the first student obtained is a junior and the second a senior would be [tex]\dfrac{12}{41}\times\dfrac{7}{40}=\dfrac{21}{410}[/tex]

Hence, the required probability is [tex]\dfrac{21}{410}[/tex].

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