Answered

A total of 70 tickets were sold for a concert and earn the organizers $804. If the cost of each ticket is either $10 or $12, how many tickets of each type were sold?
A. $18 tickets cost $10 AND 52 tickets cost $12
B. 52 tickets cost $10 and 18 tickets cost $12
C. 65 tickets cost $12 and 5 tickets cost $10
D. 5 tickets cost $12 and 65 tickets cost $10
WILL GIVE BRAINLIEST WHEN I CAN!!!!!!

Answer :

adioabiola

Answer:

52 tickets cost $10 and 18 tickets cost $12

Step-by-step explanation:

10x+12y=804. (1)

x+y=70. (2)

From (2)

x=70-y

Substitute x=70-y into (1)

10x+12y=804

10(70-y)+12y=804

700-10y+12y=804

700+2y=804

2y=804-700

2y=104

y=104/2

y=52

Recall

x+y=70

x+52=70

x=70-52

x=18

52 tickets cost $10 and 18 tickets cost $12

facundo3141592

By solving a system of equations we will see that the correct option is A.

How to write and solve a system of equations?

First, let's define the variables:

  • x = number of $10 tickets sold.
  • y = number of $12 tickets sold.

First, we know that 70 tickets were sold, so:

x + y = 70

And we know that they reached $804, then we have:

x*$10 + y*$12 = $804

Then our system is:

x + y = 70

x*$10 + y*$12 = $804

To solve this, we first need to isolate one of the variables in one of the equations, I will isolate x on the first equation:

x = 70 - y

Now we can replace that in the other equation to get:

(70 - y)*$10 + y*$12 = $804

$700 - y*$10 + y*$12 = $804

$700 + y*$2 = $804

y*$2 = $804 - $700 = $104

y = $104/$2 = 52

So, 52 $12 tickets were sold, then the other 18 tickets were $12, so the correct option is A.

If you want to learn more about systems of equations, you can read:

https://brainly.com/question/13729904

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