Answer :

bharathram3505

Answer:

Explanation:A force acting on a particle of mass 200 g displaces it through 400 cm in 2 seconds. Find the magnitude of the force if the initial velocity of the particle is zero ... A steel ball of mass 50 g is thrown vertically downwards with a velocity of 15 ... The weight of the body is 19.6N, the mass of the body is (g=9.8ms−2).

ujalakhan18

Answer:

F = 0.32 N

Explanation:

GIVEN:

Mass = m =  200 g = 0.2 kg

Distance = S = 200 cm = 2 m

Time = t = 5 s

Initial velocity = U = 0 m/s

REQUIRED

Force = F = ?

SOLUTION

Using Second Equation of Motion,

S = Ut + 1/2 at²

2 = (0)(5) + 1/2 a(5)²

2 = 25/2 a

a = 4/25

a = 0.16 m/s²

So,

Acceleration = a = 0.16 m/s²

Now Using Equation from Newtons Second Law of Motion

F = ma

F = (2)(0.16)

F = 0.32 N

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